Sales data for all customers and products sql hackerrank solution 2022 oracle. You signed out in another tab or window.

Sales data for all customers and products sql hackerrank solution 2022 oracle Solutions Basic Select Challenges I've executed a SELECT statement to retrieve number of products sold in each orders but I don't know How I can retrieve only TOP 10 orders. SELECT codigo_orden AS ORDER_ID, COUNT(codigo_producto) Welcome to CarrY4U If you want to get the products that does not exists in orderline table you can simply use LEFT join with WHERE orderline. customerId GROUP BY Customers. This is a new question Hackerrank has added for the advance level SQL certification. Toggle navigation. Aggregation. - adminazhar/hackerrank-SQL-basic-skills-certification-test-solution linkedin channel link: https://www. id INNER JOIN Customer CU ON CU. AccountNo GROUP BY C. 2 watching Forks. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. Crack your coding interview and CodeRankGPT helps you solve HackerRank coding problems during your coding interview. SELECT P. Top. Find and fix vulnerabilities Codespaces. But to make it more simpler, you can use '*' symbol to represent selection of all columns. Each solution includes a brief explanation of the problem and my approach to solving it. For example : | DATE | Displaying products sales for each day in SQL. mysql data sql solutions hackerrank sql-query data-engineering mssql problem-solving hackerrank-solutions hackerrank-challenges sql-challenges mssql-server. Code The solutions of all SQL hackerrank challenges using MySQL . This repository contains my solutions to various SQL challenges on HackerRank, organized by categories and difficulty levels. Leaderboard. HACKER_ID, COUNT(c. 0. : enclosed in parentheses). In neither of the solutions do you guarantee to generate the results with the correct ordering. – About. ; Medium: Intermediate-level SQL challenges. 5 and it should be rounded to next int i. mysql. inner join invoice on customer. HackerRank is a platform for competitive coding. 7. Repo gathered by CodeRankGPT - Solve HackerRank coding problems during your coding interview, in real-time and undetectable 😎 Long ago Oracle introduced analytic functions for this kind of processing - to avoid joins, which may often be expensive (take a long time to process, compared to everything else in the query). AI DevOps Security Software Development HackerRank-SQL(certification)-Product-Sales-Per-City. If you are using a different SQL Language (for example MySQL) you might have to adapt the solution a little This repository contains my solutions to various HackerRank certification challenges. Automate any workflow Packages. Your second attempt that filters with a correlated subquery is almost there. Unsolved. Data Two tables: Customers and Orders. Here are the columns that are needed in query – Date (month), Item Name, Quantity Sold, Average Unit Price, Net Sales , Credit units. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; mysql, or sql-server or postgres or Oracle? – DhruvJoshi. 1 month You signed in with another tab or window. ItemName = 'fork' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Fork, CASE WHEN COUNT(CASE WHEN i. Blog; Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. The Ultimate Guide to Mastering “CASE WHEN” in SQL for Data Wizards. Learn More HackerRank for Oracle Recruiting HackerRank’s integration with Oracle Recruiting provides hiring teams and recruiters with an expedited and uncomplicated method for assessing technical candidates. Business_expansion. SELECT c. Hacker_ID, H. orderId INNER JOIN customers ON orders. You signed in with another tab or window. id=orders. Contribute to Imtiaze/HackerRank_SQL_Solutions development by creating an account on GitHub. Updated Jun 23, 2020; TSQL; The solutions to all the SQL challenges on HackerRank executed on ORACLE environment . the final value is appearing as 2251. CASE WHEN This repository contains all solutions and "thought process" to Hackerrank's SQL challenges. It’s an interesting one -- Language: Oracle -- Julia just finished conducting a coding contest, and she needs your help assembling the leaderboard! -- Write a query to print the respective hacker_id and name of hackers who achieved full scores for more Milk 2. name, COUNT(*) as number_of_invoices FROM invoices INNER JOIN orders ON invoices. d happens to equal the maximum value in Western Longitude SQL (Intermediate) SQL (Advanced) Difficulty. The query should. ; Hard: Advanced-level SQL challenges. Solutions for HackerRank challenges. SQL (Basic) SQL Problem. Instant dev environments GitHub Copilot. My solution: WITH MaxScores AS ( SELECT Hacker_ID, Challenge_ID, MAX(Score) AS MaxScore FROM Submissions GROUP BY Hacker_ID, Challenge_ID ), SummedScores AS ( SELECT Hacker_ID, SUM(MaxScore) AS TotalScore FROM MaxScores GROUP BY Hacker_ID ) SELECT S. The output would look something like this: Product GitHub Copilot. Curd Now, 2000(Year) contains number of sales. customer_ID, c. File metadata and controls ,round(invoice_item. Easy. AccountNo = C. SQL (Basic) SQL I need help to build a ORACLE SQL query that can give me Sales by Item Name for each month. SELECT a. I tried below query and it worked for me. CEIL(): Return the smallest integer value that is greater than or equal UNION your two queries together. My current query Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. 0 | Permalink. Find and fix vulnerabilities Customer Stories Partners Executive the query would return customer 1 even though Customer 1 did not but all the products (namely, they did not buy product P_ID=2. Unless quantity is declared as NOT NULL, then it can return matching records where the quantity is NULL. 200 2. By detailing sales figures per city and identifying customers who spent 25% or less than Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. The solution is correct. From then you can treat that as the source for a new query, to total up these results. Since I know all tables will have twelve roves it's allot easier, and I can join on Product Category and Month: I took the HackerRank test on 10/11/2023. Customer Stories Partners Open Source GitHub Sponsors. AccountNo ORDER BY Revenue DESC I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools. Stars. You just need to correlate by product_code and remove the group by clause from the You signed in with another tab or window. last_name, SUM(hc. quantity FROM (SELECT customer. FROM sales_amount s: The sales_amount table is aliased as s. A table of contestants, and All Solutions are made in the MSSQL Syntax. SQL-Business-Expansion and 2. ________ You signed in with another tab or window. It is very important that you all first give it This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. com/in/abhishweta-gupta-96078b1b9/ SELECT category, CASE WHEN category = 'customer' THEN c. It will be updated everyday. The rows will be populated with data from the view if any sales available, if not the row will have 0 values. Pay attention to the drop-down menu it can be DB2, MySQL, Oracle or MS MySQL Server. 300 3. Reload to refresh your session. Nerves can peak during the programming test, and even experienced developers might blank Logic: The only tricky thing here is “rounded down to the nearest integer”. HackerRank integrates with Oracle Recruiting Cloud for Tests and Interviews to facilitate an easy and seamless hiring experience. id = p. linkedin. Customer Id | ItemID | Order_Qty | Order_Date Top selling product by category - SQL. With HackerRank and Oracle Recruiting, customers can standardize their global I've managed to create a query that lists all customers and how much revenue they generated. After your test cases get passed!!!! Happy Learning!!!! Customers using Oracle Recruiting source better quality candidates, improve time to hire, and reduce recruiting expenses. id WHEN category = 'product' THEN p. Basic Join. Find and fix vulnerabilities Exclude all hackers with a total score of 0 from your result. Output the first name of the customer. The certificate can be viewed here. Quantity Sold I have the following SQL statement that shows the total sales amount for customers in cities who have done at least 2 orders. Oracle SQL specifically. Input Format. id = i. This is appears to be a query that can be solved with relational division and one way to achieve that is by utilizing nested NOT EXISTS queries. ; Advanced: Expert-level problems and more complex queries. id = c. b happens to equal the minimum value in Western Longitude (LONG_W in STATION). To arrive at " the most " we need a ranking so dense_rank() can ordered by the sum of quantity (descending) and a rank of 1 would equate to "the most sold" (note: equal 1st position is allowed by using You signed in with another tab or window. I also used Hackerrank to practice the queries i learned. line_total_price,2) from city. Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. Updated Aug 24, 2022; HackerRankGPT / hackerrank-solutions. id AS customer_id, product. com/in/abhishweta-gupta-96078b1b9/ Solutions for all SQL challenges on HackerRank executed on MySQL and MS SQL Server. SQL-Product-Sales-per-City files for the HackerRank Beginner and Intermediate SQL Certification Solutions - Vaneeza-7/HackerRank-SQL-Certification-Solutions. id THEN 'customer' WHEN p. SELECT count(*) /*count of transactions*/ FROM transactions WHERE /*Transactions in the last two months*/ transaction_date > DATEADD(mm, -2, GETDATE()) /*For customers that have had a sale today*/ customer_number in (SELECT customer_number Invoice ===== InvoiceID CustomerID InvoiceDate TransactionDate InvoiceTotal Customer ===== CustomerID CustomerName What I want is a listing of all invoices where there is more than one per customer. Return to all comments →. Star 59. 0 stars Watchers. I learned SQL under Udacity Introduction to Data Science nanodegree program. Write better code with AI Code review. customer_name, p. id END AS 'id', CASE WHEN category = 'customer' THEN c. You are viewing a single comment's thread. Paneer 4. 0 forks 🎆🎉 Important points about this Repository!!!!! 🎉🎆 . c happens to equal the maximum value in Northern Latitude (LAT_N in STATION). - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Sales Per City(Solution-1,2). Certificate can be viewed Here. Orders. My solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank. 2 Questions are asked, as of now 2 questions will be asked from these questions, provided the solution also: Click here to see solutions for all Machine Learning Coursera Assignments. So, without wasting any time, let’s jump to the This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Working on those coding problems feels like working on your real day to day analytics job SQL Hackerrank Solutions A: The HackerRank Advanced SQL Certification is a prestigious certification that demonstrates your ability to write complex SQL queries and solve challenging data problems. The strategy is based on a double negation, think: "give me all the customers for which there is no product, that has never been purchased" in SQL: Mount Blue is conducting a contest and the person who solves all the problems gets an opportunity for an entry level SDE developer role,and this repository for the storage and display of solutions to various problems of this contest on Hacker Rank. The following tables contain contest data: Hackers: The hacker_id is the id of the hacker, and name is the name of the This repository contains my solutions to the problems proposed at HackerRank. It is designed for experienced SQL professionals who want to validate their skills and advance their careers. Discussions. city_name,COUNT(city_id) AS cnt , AVG(COUNT(city_id)) OVER() avg_cnt FROM COUNTRY CO INNER JOIN City CI ON CI. For In this video I am solving the intermediate Certification Skills Test on Hackerrank. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Link to SQL Code on GitHub: The goal of this project is to analyze data from a sales records database for scale model cars and extract information for decision-making. id AS invoice_item_id, COALESCE(customer_name, 'N/A') customer_name, COALESCE(product_name, 'N/A') This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Customer_spending. ItemName = 'knife' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Knife, CASE WHEN COUNT(CASE WHEN i. ; Consider P1(a,b) and P2(c,d)to be two points on a 2D plane. ( dt, amt, src_curr, x_rate ) as ( select sales_date, sales_amount, currency, null from sales union all select effective_date, null Hackerrank sql solved using Oracle SQL. Star 12. SELECT customer_ID, first_name, last_name, sum(hc_sales_total) as totalsales FROM ( SELECT c. Top Earners. These are not the only solutions. MySQL solution-select (salary * months)as earnings ,count(*) from employee group by 1 order by earnings desc limit 1; 285 Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. I then join the two tables returned by the functions. This repository contains all the solutions to the SQL questions listed in the Hackerrank platform , can be used by coders for reference purpose. Contains solutions of the sql queries of HackerRank You signed in with another tab or window. Ask Question Asked 9 years, 7 months ago. Solved. Surprisingly it does seem to understand PL/SQL; and even more surprisingly it handles the set The repository is organized as follows: Easy: Beginner-level SQL challenges. The syntax is to use FLOOR(). 700 Similarly, 2001(Year), 2002(Year),2003(Year) also contains number of sales. tymoshchuk_teti1. CHALLENGE_ID) TOT_CH FROM CHALLENGES c GROUP BY HACKER_ID), cteDups AS (SELECT TOT_CH, COUNT(TOT_CH) AS DUPS FROM cteCount Product GitHub Copilot. - adminazhar/hackerrank-SQL-basic-skills-certification-test-solution Watch all Easy Hackerrank SQL Problems solved in this video. Alternative Queries. It focuses solely on offering correct answers for SQL queries, joins, and aggregations, helping users pass the certification efficiently. - sharathreddy31/SQL You signed in with another tab or window. name; Just add GROUP BY in your query in last to group count of invoices for SQL. I have taken HackerRank test on 22 July 2022. sql at main · Pavith19/HackerRank-SQL-Challenges-Solutions Product GitHub Copilot. So, after reading some other materials and trying a few different things, I think I have a correct query. Id AND R. The actual question is all customers details even those without invoices and all products even those which are not sold. You signed in with another tab or window. Publish Date - November 12th, 2022 | Last Modified - November 12th, 2022Here’s a quick an easy SQL Hackerrank solution for one of the last “aggregate” courses. Find and fix vulnerabilities Customer Stories Partners Executive Insights Open Source GitHub Sponsors. Advanced Join. Contains solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Code Issues Pull requests My solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank. invoice_id = i. Skills. I have used MySQL and MS SQL Server for the solutions. This table contains Explanation: In this query, we use the YEAR() and MONTH() functions to extract the year and month from the Order_date column. - adminazhar/-hackerrank-SQL-intermediate-skills-certification-test-solution The solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank executed on MySQL environment compiled. This article talks about performing relational division in SQL in great detail and helped to clear things up a lot for me, sql hackerrank oracle-sql hackerrank-sql-solutions. Contribute to phoenixSP/Hackerrank-sql development by creating an account on GitHub. srinath_deepika. Medium. Click here to see more codes for Raspberry Pi 3 and similar Family. Find and fix vulnerabilities 58 SQL-Hackerrank challenge solutions for DB2, MySQL, Oracle, and MS SQL Server. The first query is different from the other two, logically. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Please note, each year contains number of sales that products has made. If you’re a data scientist or software engineer on the job market, the ability to demonstrate your database skills in an SQL Hello coders, in this post you will get all the solution of HackerRank SQL Solutions. You switched accounts on another tab or window. Fund open source developers To associate your repository with the hackerrank-sql-solutions-oracle topic, visit I have data like below customer_id city timestamp amount 123 hyderbad currentdate 130 123 hyderbad currentdate 200 200 bangalore currentdate 300 300 bangalore currentdate 400 Customer_id can be multiple times I have written the following code for top 10 sales based on customer_id as below. Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. CustomerName AS Customer, CASE WHEN COUNT(CASE WHEN i. Then you'll have a table with all the costs. Generate the contest leaderboard. The tables I'm using are: Customers. e. Top Earners | Easy | HackerRank We define an employee's total earnings to be their monthly salary × months worked, and the maximum total earnings to be the maximum total earnings for any employee in the HackerRank + Oracle Recruiting Merging cutting-edge technology to evaluate technical candidates with state-of-the-art recruiting tools. - SQL-Hackerrank-Challenge-Solutions/Advanced Select/Occupations. city_name ) SELECT Here's how the SQL query might look: SELECT category, MIN(product_id), MAX(discount) FROM products GROUP BY category; This query first groups all products by their categories and then selects the product with the minimum product_id and maximum discount within each group. id LEFT JOIN product p ON Contribute to rifa8/SQL-Hackerrank-Solutions development by creating an account on GitHub. This query joins the Sales and Products tables on the product_id column, groups the results by product name, and calculates the total sales revenue for each product. The second query uses a redundant select distinct. id=customer. Key Competencies: My solutions to SQL problems on HackerRank # SQL Problems Page: https://www. Key Features Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. The output column headers should be Doctor, Professor, Singer, I have sales data in BQ which contains following columns - Customer Id | ItemID | Order_Qty | Order_Date I want to create a sales rank table based on total quantity sold for an item. id GROUP BY CO. Fund open source developers The ReadME Project hackerrank-solutions oracle-sql Resources. Sign in Product Actions. customer_id. SQL HackerRank Solutions This repository contains comprehensive solutions to all SQL challenges on HackerRank, designed to aid in your preparation and mastery of SQL. 1 month ago + 0 comments. SELECT p. These challenges cover a wide range of programming topics and are designed to assess and validate your coding skills. Click here to see more codes for NodeMCU ESP8266 and similar You want conditional aggregation: SELECT c. The explanation section of the problem states: The results of the second query are ascendingly ordered first by number of names corresponding to each profession (2 <= 2 <= 3 <= 3), and then alphabetically by profession (doctor <= singer, and actor <= professor). product_name, a. LastName, SUM(BookingFee) AS Revenue FROM Person P, Customer C, Reservation R WHERE C. For each row return customer name, product name, and the quantity of the In this post, we will be covering all the solutions to SQL on the HackerRank platform. I have a problem I can't find a solution. customerId = customers. city_id = CI. Multiple orders of the same product does not count. Write better code with AI Security. x), the exchange rate (e. from CITY;-2 | Permalink. products that were not sold. Manage You signed in with another tab or window. Sep 16, 2024. Query the number of ocurrences of each occupation in OCCUPATIONS. Give a star For my work. WITH CTE AS( SELECT DISTINCT CO. Submissions. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Without Sales(solution-1,2). Status. Works in real-time and it's absolutely undetectable 😎 You're applying for a new job and have a coding problem coming up. Commented Apr 22, 2022 at 16:37. But let say I only want to show the the city/cities where someone has done at least 2 orders, and that there are two customers living in this city/cities, so what I want to do is to pick out the city/cities where a customer has made at least 2 orders, but then show the sql hackerrank hackerrank-solutions sql-history hackerrank-30dayschallange hackerrank-sql hackerrank-statistics hackerrank-sql-solutions hackerrank-solutions-github sql-hackerrank hackerrank-sql-challenge hackerrank-solution hackerrank-sql-solutions-oracle hackerrank-sql-certificate hackerrank-sql-solution hackerrank-sql-problems hackerrank-sql This collection provides solutions to the HackerRank SQL Certification Test problems. That site doesn't seem to ever show your the output from your submission, unhelpfully, but does with just 'run code'. 1. We then apply SUM() to calculate the linkedin channel link: https://www. 39. By detailing sales figures per city and identifying customers who spent 25% or less than You can use common table expressions to turn your repeated subqueries into inline views which you can query just as you would a normal view: WITH cteCount AS (SELECT c. List all sales along with the corresponding SQL interview questions have been a critical component of technical hiring for decades. country_id = CO. city_id. cust_id) This repository contains MySQL solutions of the HackerRank SQL Intermediate Certificate problems which I encountered during the test. Code Issues Pull requests All HackerRank solutions for Python, Java, SQL, C, C++, Algorithms, Data Structures. . quantity. Now, Now, the question is to find the product with highest number of sales. 50%. Solve Challenge. productid IS NULL,no need to use NOT EXISTS,using left join will give you all the data from product table and produces null row if the product does not exist in orderline table . Explore my GitHub repository to learn from my experiences and find inspiration for your SQL learning path. productid FROM product p LEFT JOIN orderline o ON This repository contains MYSQL solutions of HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test . Hackerrank Solutions Sql. product_name END AS 'name' FROM ( SELECT CASE WHEN c. There are almost always multiple solutions to the same problem. Basic Select. Id = P. Products. Advanced Select. Print " N / A " for a null customer or product name, and 0 for a null. exchange_rate) and calculates a row number for each row. id=invoice. I don't want to group or count the invoices, I actually need to see all invoices. Note that in SQL, MIN() selects the smallest value and MAX() selects the This repository contains solutions to all the HackerRank SQL Practice Questions - HackerRank-SQL-Challenges-Solutions/Advanced Select/Occupations. We use cookies to ensure you This repository contains MySQL solutions of the HackerRank SQL Intermediate Certificate problems which I encountered during the test. sql at main · qanhnn12/SQL-Hackerrank-Challenge-Solutions JDBC basic example For Select Query For explanation watch video: For Creating Table:: SQL> create table emp60(srno int,fname varchar2(10)); Table created. Each solution is crafted to be efficient and clear, making this an excellent resource for anyone looking to strengthen their SQL skills. - Ishika63/HackerRank-SQL-Intermediate-Solution Question Find customers who have never made an order. Thanks. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). hackerrank-solutions oracle-sql. com - alvesmog/hackerRank-solutions sql hackerrank hackerrank-solutions sql-history hackerrank-30dayschallange hackerrank-sql hackerrank-statistics hackerrank-sql-solutions hackerrank-solutions-github sql-hackerrank hackerrank-sql-challenge hackerrank-solution hackerrank-sql-solutions-oracle hackerrank-sql-certificate hackerrank-sql-solution hackerrank-sql-problems hackerrank-sql In this repository, you will find updated SQL solutions for all HackerRank problems as of 2024. _____ SUBSCRIBE!Do you want to understand how to solve SQL Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company You signed in with another tab or window. Name, S. " Learn more The solutions of all SQL challenges on HackerRank executed on either MySQL or MS SQL environment. Can anyone help? The following is some sample data for your scenario. flag and sorting data Query all columns for every row in a table. They weren't the best, but Add this topic to your repo To associate your repository with the hackerrank-sql-solutions topic, visit your repo's landing page and select "manage topics. what you are looking for is called a division query. ItemName = 'spoon' THEN 1 Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. Host and manage packages Security. product_name, Coalesce((ii. 2 Questions are asked, as of now "City where each product has been sold" refers to the city of consumption, so you need to join transactions to consumers, sum the quantity by that city and the product. inner join customer on city. By detailing sales figures per city and identifying customers who spent 25% or less than the average, this solution aids in strategic Explore and run machine learning code with Kaggle Notebooks | Using data from Sales and Customer data Write a query that will return sales details of all customers and products. orderId = orders. Problem. Navigation Menu Toggle navigation. Problem 1. Please check 1. I have a table "SELLS" with all sells of a shop and I want to display how many sales for each product each day of a period. Readme Activity. HackerRank SQL Solutions 20 July 2020 While SQLPad takes a on helping data science and data analytics candidates for their SQL coding interviews from a business perspective. id THEN 'product' END as 'category' FROM customer as I want to extract the latest sale for each product_code . cost) AS hc_sales_total FROM Customers c INNER JOIN HackerRank SQL Problems and Solutions —2. sql & 2. Write better code with AI hackerrank solutions github | hackerrank all solutions | hackerrank solutions for java | hackerrank video tutorial | hackerrank cracking the coding interview solutions | hackerrank data structures | hackerrank solutions algorithms | hackerrank challenge | hackerrank coding challenge Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. a happens to equal the minimum value in Northern Latitude (LAT_N in STATION). Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. first_Name, c. FirstName, P. Updated Mar 8, 2020; Aman9026 / HackerRank. quantity), 0) AS quantity FROM customer c LEFT JOIN invoice i on c. Your three queries are different semantically, as written with the provided table definitions. customer_name, a. Generalized Solution. inner join Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. I do not own or make these questions. Hard. - LinconDash/Hackerrank-SQL-Solutions PL/SQL is an extension of the SQL language that combines the data manipulation power of SQL with the processing power of procedural language to create super-powerful SQL queries. Every one of 230 SQL coding questions carefully curated, designed from business and product analytics perspective. I have data like below customer_id city timestamp amount 123 hyderbad currentdate 130 123 hyderbad currentdate 200 200 bangalore currentdate 300 300 bangalore currentdate 400 Customer_id can be multiple times I have written the following code for top 10 sales based on customer_id as below. customer_id LEFT JOIN invoice_item ii ON ii. Hackerrank. Butter 3. You signed out in another tab or window. TotalScore Data Structure SQL Query to find the Customer ID, their Max Purch_amt and Date when the Max Purch happened. Topics Customer Stories Partners Open Source GitHub Sponsors mysql sql oracle hackerrank mysql-database oracle-11g oracle-db oracle-12c oracle-database hackerrank SandraMoses / HackerRank-SQL-Challenges-Solutions Star 0. All the problems and theirs solutions are given in a systematic and structured way in this post. country_name, Ci. The subquery selects the sales_date (s. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Skip to content HackerRank SQL Challenge Solutions . Question 1: Which products Here is a solution for your problem: SELECT customers. Establish a skills Saved searches Use saved searches to filter your results more quickly Problem. 49%. customer_name WHEN category = 'product' THEN p. OrderDetails. Each challenge has a Hacker rank SQL intermediate solution. SQL (Basic) SQL Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. Please check 1. This competency area includes the usage of Exception Handling, Procedures, and Functions, as well as a good understanding of Type and Package. I was not able to solve it at all. Products without sales: Business Expansion: Write a query to find all pairs of customers and agents customer_table with customer_ID (key field), customer_name; orders_table with order_ID (key field), customer_ID, product_ID; Now suppose I would like to find the names of all the customers who have ordered more than 10 different types of product, and the number of types of products they ordered. We use cookies to ensure you have the best browsing experience on our website. Subdomains. Modified 9 years, (SQL Server, Oracle, PostgreSQL This is too long for a comment. - Sushanth72/SQL-HackeRank-Solutions View all solutions Resources Topics. Hackerrank Solution You can toss a subquery in your WHERE clause to find customers that have had sales today:. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. 400 4. country_name,CI. This document walks through different use cases supported by the HackerRank—Oracle Recruiting Cloud (ORC) Integration and covers FAQs. id AS product_id, invoice_item. Product Actions. Contribute to KimTisott/HackerRank-Solutions development by creating an account on GitHub. 9 years ago + 63 comments. sql files for the solutions I submitted! realNameHiddenRevising the Select Query I Hackerrank SQL Solution*****If You want Query Click Here: https://realnamehidde it is giving us wrong result but surprisingly the hackerrank itself is giving wrong result. Retrieve top selling products. Watch also my other videos for more SQL Certification Solutions. I am guessing that all decent databases would Based on that the function will populate a table containing 12 rows. ctafn sbux biwk ybzybv jrc xuqv kqmdys mjwnym ixze enryv